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With the tab and line feed values, the statements are harder to read, but they still work just the same For example, if you display the strTC variable in a dialog box, you see the four lines (see Figure 5-1) If you prefer, you can type the values directly into a string in AppleScript Editor You can also use the constants shown in Table 5-1 These are useful when you re putting together a string from different components For example, the following statements declare string variables for the different components of an address, build from them a string containing the full address, and then display the string in a dialog box:

When an inductance, capacitance, and resistance are connected in series (Fig 16-4), the resistance R can be imagined as belonging entirely to the coil, when you use the preceding formulas Then you have two vectors to add, when finding the impedance of the series RLC circuit containing three such components: Z = (R + jX L ) + (0 + jXC) = R + j(XL + XC ) Again, remember that XC is never positive! So, although the formulas here have addition symbols in them, you re adding a negative number when you add in a capacitive reactance

generates the following parameterized query:

(@p0 varchar(7))SELECT [t0].[au_id], [t0].[au_lname], [t0].[au_fname], [t0].[phone], [t0].[address], [t0].[city], [t0].[state], [t0].[zip], [t0].[contract] FROM [dbo].[authors] AS [t0] WHERE [t0].[city] = @p0

set set set set set set set FirstName to "Megg" MiddleInitial to "A" LastName to "Byte" strAddress1 to "8192 Giggs St" strAddress2 to "Apt AF" strCity to "City of Industry" Zip to "CA 91745"

Problem 16-5 Suppose a resistor, a coil, and a capacitor are connected in series with R = 50 , XL = 22 , and XC = 33 What is the net impedance, Z Consider the resistor to be part of the coil, obtaining two complex vectors, 50 + j 22 and 0 j33 Adding these gives the resistance component of 50 + 0 = 50, and the reactive component of j22 j33 = j11 Therefore, Z = 50 j11 Problem 16-6 Consider a resistor, a coil, and a capacitor that are connected in series with R = 600 , XL = 444 , and XC = 444 What is the net impedance, Z Again, imagine the resistor to be part of the inductor Then the complex impedance vectors are 600 + j444 and 0 j444 Adding these, the resistance component is 600 + 0 = 600, and the reactive component is j444 j444 = j0 Thus, Z = 600 + j0 This is a purely resistive impedance, and you can rightly call it 600 Problem 16-7 Suppose a resistor, a coil, and a capacitor are connected in series The resistor has a value of 330 , the capacitance is 220 pF, and the inductance is 100 H The frequency is 715 MHz What is the complex impedance of this series RLC circuit at this frequency First, calculate the inductive reactance Remember that XL = 628f L and that megahertz and microhenrys go together in the formula Multiply to obtain the following:

The same Entity Framework query generates a T-SQL query with a string literal, to get the parameterized query you ll need to use the LINQ to Entities query:

set FullAddress to FirstName & space & MiddleInitial & space & LastName & linefeed & strAddress1 & linefeed & strAddress2 & linefeed & strCity & tab & Zip display dialog FullAddress

string city = "Oakland"; var query = from a in ctx.Authors where a.city == city select a;

jXL = j(628 715 100) = j4490 Next, calculate the capacitive reactance using the formula XC = 1/(628f C ) Convert 220 pF to microfarads to obtain C = 0000220 F Then calculate: jX C = j[1/(628 715 0000220)] = j101 Now, lump the resistance and the inductive reactance together, so one of the impedance vectors is 330 + j4490 The other is 0 j101 Adding these gives Z = 330 + j4389; this rounds off to Z = 330 + j4390